y^2-4+4y+1=0

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Solution for y^2-4+4y+1=0 equation:


Simplifying
y2 + -4 + 4y + 1 = 0

Reorder the terms:
-4 + 1 + 4y + y2 = 0

Combine like terms: -4 + 1 = -3
-3 + 4y + y2 = 0

Solving
-3 + 4y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '3' to each side of the equation.
-3 + 4y + 3 + y2 = 0 + 3

Reorder the terms:
-3 + 3 + 4y + y2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 4y + y2 = 0 + 3
4y + y2 = 0 + 3

Combine like terms: 0 + 3 = 3
4y + y2 = 3

The y term is 4y.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4y + 4 + y2 = 3 + 4

Reorder the terms:
4 + 4y + y2 = 3 + 4

Combine like terms: 3 + 4 = 7
4 + 4y + y2 = 7

Factor a perfect square on the left side:
(y + 2)(y + 2) = 7

Calculate the square root of the right side: 2.645751311

Break this problem into two subproblems by setting 
(y + 2) equal to 2.645751311 and -2.645751311.

Subproblem 1

y + 2 = 2.645751311 Simplifying y + 2 = 2.645751311 Reorder the terms: 2 + y = 2.645751311 Solving 2 + y = 2.645751311 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + y = 2.645751311 + -2 Combine like terms: 2 + -2 = 0 0 + y = 2.645751311 + -2 y = 2.645751311 + -2 Combine like terms: 2.645751311 + -2 = 0.645751311 y = 0.645751311 Simplifying y = 0.645751311

Subproblem 2

y + 2 = -2.645751311 Simplifying y + 2 = -2.645751311 Reorder the terms: 2 + y = -2.645751311 Solving 2 + y = -2.645751311 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + y = -2.645751311 + -2 Combine like terms: 2 + -2 = 0 0 + y = -2.645751311 + -2 y = -2.645751311 + -2 Combine like terms: -2.645751311 + -2 = -4.645751311 y = -4.645751311 Simplifying y = -4.645751311

Solution

The solution to the problem is based on the solutions from the subproblems. y = {0.645751311, -4.645751311}

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